Moment & Couple
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M = r x F
M : Moment (Nm)
F : Force (N)
r : Arm (m)
The moment of force is a vector quantity
that represents the magnitude of force applied
to a rotational system at a distance from the axis of rotation.
unit for moment is the Newton metre (Nm).
A (force) moment is a measure of the amount of rotation effect due to the working
force. The effect depends both on the force and the force arm r.
The moment M is
a vector quantity, with its axis orthogonal to the plane spawned by F and r.
M = d x F
A special case of a moment is a couple. A couple consists of two parallel
forces that are equal in magnitude, opposite in sign and do not share a line of
action. It does not produce any translation, only rotation. The resultant force
of a couple is zero. But, the result of a couple is not zero; it is a pure moment.\
A couple is used to describe the rotational effect of two equal forces that do not
share a line of action. A couple (or torque) is much used in mechanical engineering.
For example, a combustion engine delivers torque at its shaft, which can be used
to drive equipment. As stated, a couple is a pure moment and as such can only
be destroyed by a couple with a counter effect. Otherwise, the total sum of the forces
will not be zero.
We examine the tail rotor of a helicopter. This rotor is also called the anti torque
rotor, as its purpose is to counteract the reaction torque on the fuselage as a
result of the applied torque to the main rotor by the engine and transmission. When
this reaction torque is not cancelled, the fuselage will rotate. The anti torque
rotor functions by introducing a moment, which consists of a thrust vector F which works
over the arm 'l' with origin O. This origin O lies on the main rotor shaft. We assume
a right angle between the arm 'l' and the tail rotor thrust vector F. The helicopter
engine produces a torque of 500 Nm during a hover. The length of 'l' is 5 metres. What
force F is needed to prevent the fuselage from spinning?
When we assume a right angle between the arm 'r' and the tail rotor thrust vector
so the vector products of F and r resolve to the product of their magnitudes.
The moment M must counteract the torque
of 500Nm; in other words, the sum of the torque and the moment must be zero.
This leads to the equation 500 + 5F = 0 -> F = -100N. The minus sign indicates the direction needed to cancel out the
effect of the applied engine torque.
Will this result in equilibrium in a helicopter? As the sum of moments is zero,
the helicopter will not rotate. However, for an object to be in equilibrium, both
the sum of moments and the sum of forces in all directions must be zero. We now
look at the sum of forces in the plane of rotation, as these are the only relevant
forces in this example. These forces are the couple of 500 Nm and the moment of
-500Nm. We know that the couple (torque) will not introduce any translational force
The sum of the couple is therefore 0. We now look at the anti torque moment
of -500 Nm, which uses a force of 100N. As the torque forces are cancelled out, this is
the only component left. Conclusion: the sum of all forces is 100 N (500 - 500 + 100).
This force will move the helicopter sidewards! This result should be expected, because
a couple (torque) can only be cancelled by another couple, which is not the case
with the tail rotor produced moment.
Some manufacturers design their helicopters with the main rotor shaft tilted a number
of degrees, in order to counteract the translational force with main rotor thrust. Another solution
is to offset the cyclic blade pitch to produce a similar cancelling
out thrust vector from the main rotors.